0.0054x^2+1.46x+95.11=143

Solution for 0.0054x^2+1.46x+95.11=143 equation:

0.0054x^2+1.46x+95.11=143

We move all terms to the left:

0.0054x^2+1.46x+95.11-(143)=0

We add all the numbers together, and all the variables

0.0054x^2+1.46x-47.89=0

a = 0.0054; b = 1.46; c = -47.89;
Δ = b2-4ac
Δ = 1.462-4·0.0054·(-47.89)
Δ = 3.166024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.46)-\sqrt{3.166024}}{2*0.0054}=\frac{-1.46-\sqrt{3.166024}}{0.0108}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.46)+\sqrt{3.166024}}{2*0.0054}=\frac{-1.46+\sqrt{3.166024}}{0.0108}
$